Scriptproblem
| From: | Ruprecht Helms | Date: | Tue, 24 Jan 2006 15:12:53 +0000 |
| Subject: | Scriptproblem | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-41133@lists.php.net to get a copy of this message | ||
Hi,
how can I display the stored data of an user as value in a formfield.
Actualy the formfield "vorname" shows no entry and the formfield "name" shows .$row->Name.
What is the correct syntax in this case.
Regards,
Ruprecht
<?
mysql_connect("localhost",<user>,<password>);
$result=mysql_db_query("salzert","SELECT * FROM Benutzer WHERE ID=$id");
echo '<input type="text" name=id value="';
echo $id;
echo '">';
echo "<tr>";
echo " <td>Vorname</td>";
echo '<td><input type="text" name="vorname" value="';
echo $row->Vorname;
echo '"></td>';
echo "</tr>";
echo "<tr>";
echo " <td>Name</td>";
echo '<td><input type="text" name="name" value=".$row->Name."></td>';
echo "</tr>";
...
?>