RE: [PHP-DB] Scriptproblem
| From: | Bastien Koert | Date: | Tue, 24 Jan 2006 15:40:54 +0000 |
| Subject: | RE: [PHP-DB] Scriptproblem | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-41134@lists.php.net to get a copy of this message | ||
You seem to be mixing OO and procedural coding styles...try
<?
mysql_connect("localhost",<user>,<password>);
$result=mysql_db_query("salzert","SELECT * FROM Benutzer WHERE ID=$id");
$row = mysql_fetch_array($result); //get the data into an array
echo '<input type="text" name=id value="';
echo $id;
echo '">';
echo "<tr>";
echo " <td>Vorname</td>";
echo '<td><input type="text" name="vorname" value="';
echo $row['Vorname'];
echo '"></td>';
echo "</tr>";
echo "<tr>";
echo " <td>Name</td>";
echo '<td><input type="text" name="name" value=".$row['Name']."></td>';
echo "</tr>";
...
?>
bastien
From: Ruprecht Helms <rhelms@my-mail.ch> Reply-To: rhelms@my-mail.ch To: php-db@lists.php.net Subject: [PHP-DB] Scriptproblem Date: Tue, 24 Jan 2006 16:12:53 +0100 Hi, how can I display the stored data of an user as value in a formfield. Actualy the formfield "vorname" shows no entry and the formfield "name" shows .$row->Name. What is the correct syntax in this case. Regards, Ruprecht <? mysql_connect("localhost",<user>,<password>); $result=mysql_db_query("salzert","SELECT * FROM Benutzer WHERE ID=$id"); echo '<input type="text" name=id value="'; echo $id; echo '">'; echo "<tr>"; echo " <td>Vorname</td>"; echo '<td><input type="text" name="vorname" value="'; echo $row->Vorname; echo '"></td>'; echo "</tr>"; echo "<tr>"; echo " <td>Name</td>"; echo '<td><input type="text" name="name" value=".$row->Name."></td>'; echo "</tr>"; ... ?> -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php