Re: how to handle exception in php
| From: | Luiz Alberto | Date: | Sun, 02 May 2010 13:32:31 +0000 |
| Subject: | Re: how to handle exception in php | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-47125@lists.php.net to get a copy of this message | ||
Dear Bavithra,
I would suggest you the following solution
$sql = "SELECT x FROM y";
$rs = mysql_query ($sql)
$num = mysql_numrows($rs);
while ($i < $num){
z = mysql_result($rs, $i, 'x');
$i++;
}
I hope that above solution help you.
Luiz Alberto
On Sun, 2010-05-02 at 10:56 +0530, Bavithra R wrote:
> hi friends
>
> I am doing a simple student mark details project.
> for calculating rank I need to compare the total marks one by one.
> To do so i use *for loop.* so atlast while reaching the end of the table it
> shows the following warning.
> *
> Warning*: mysql_result()
>
> [function.mysql-result<http://127.0.0.1/pro/function.mysql-result>]:
> Unable to jump to row 18 on MySQL result index on line *50*
>
> It is because it has no next value to compare.How to use try..catch
> exception handling in this.?Or any other suggestion.
> Can anybody help me
>
> --Bavithra