Re: how to handle exception in php

On 2 May 2010 06:26, Bavithra R <bavithra.r@gmail.com> wrote: > hi friends > > I am doing a simple student mark details project. > for calculating rank I need to compare the total marks one by one. > To do so i use *for loop.* so atlast while reaching the end of the table it > shows the following warning. > * > Warning*: mysql_result() > > [function.mysql-result<http://127.0.0.1/pro/function.mysql-result>]: > Unable to jump to row 18 on MySQL result index on line *50* > > It is because it has no next value to compare.How to use try..catch > exception handling in this.?Or any other suggestion. > Can anybody help me > > --Bavithra > Commonly the while loop looks like ... while ($row = mysql_fetch_assoc($result)) { If you intend to use this for other loops, watch out where the result of the function is False to indicate the end of the iterations. while (False !== ($row = mysql_fetch_assoc($result))) { Whilst this offers nothing extra here, for functions where 0 or "" are valid responses and False is the "get me out of here" response, testing for type and value (!==) is important. -- ----- Richard Quadling "Standing on the shoulders of some very clever giants!" EE : http://www.experts-exchange.com/M_248814.html EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731 ZOPA : http://uk.zopa.com/member/RQuadling