PHP 4.0 Bug #4751: fopen within if is not executed
| From: | s dot frings at edvfrings dot de | Date: | Thu, 01 Jun 2000 10:30:17 +0000 |
| Subject: | PHP 4.0 Bug #4751: fopen within if is not executed | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-19946@lists.php.net to get a copy of this message | ||
From: s.frings@edvfrings.de
Operating system: Linux
PHP version: 4.0.0 Release
PHP Bug Type: Misbehaving function
Bug description: fopen within if is not executed
I tried to open two files and check if both were opened:
if ($source=fopen("data.txt","r") &&
$dest=fopen("data.tmp","w"))
{
do something;
}
This worked fine in PHP3. The destination file will be opened but the source file not. If I try to
use the variable $source for a read command I get an error message that this is not a file handle.