evaluating PHP source to a file.

Hi, can anyone point me to a direction, how to solve the following problem? I'm quite experienced in web programming, but it's my first project with PHP. I have a small content management system, from which I have to generate a static snapshot. I have: * a template (which I can modify in any way if necessary) * contents of the site in a table, which contains the following fields: - filename (which the output file needs to be) - page type (either "text" or "php", read below) - source now i need to go through the content table and generate static versions of all the pages on the template. for the "text" type pages the content needs to be the source in the table, for the "php" type pages it needs to be the output of the php source in table. in my humble mind (and with my previous EmbPerl experience) i thought up a following solution: * create the template as a PHP source, and let the content part be something like: --- 8< --- global $pagedata; if ($pagedata["pagetype"]=="php") eval($pagedata["src"]); else echo $pagedata["src"]; --- 8< --- * now in the "publish" page, create a loop that goes through all the pages in the database: --- 8< --- $query="SELECT filename,pagetype,src FROM pages"; $res=mysql_query($query); while($row=mysql_fetch_array($res)) { $pagedata["pagetype"]=$row["pagetype"]; $pagedata["src"]=$row["src"]; $FD=fopen($row["filename"],"w"); --> $content=eval($template); fwrite($FD,$content); fclose($FD); } mysql_free_result($res); --- 8< --- The problem is how to catch the contents of the eval to a variable and not print it out on a page. Can anyone share an idea? This thing needs to be running by Sunday night, so I'm really out of time here. And: I'm NOT SUBSCRIBED to these lists, so please answer in a private mail. Rgds, Tfr --==< tfr@cafe.ee >==< http://tfr.cafe.ee/ >==< +1-504-4467425 >==--