Re: do_declare_property()

Hi John! On Wed, 12 Jul 2000, John Keiser wrote: > > Of course it will know it's a class, and when parsing the class def. > > the rewrite takes place. > > > > Of course, we don't really need to have `$this->__bar', I though we > > can also have private var $bar', and rewrite the member to > > _Class__bar' > > to ensure it's `privateness'. > > > > Simple question. Couldn't you have a normal public variable that happened > to start with two underscores? Isn't there a $ or something that cannot be > used in an ordinary variable that could be used for this internal marker? > > What would happen in the following example: > > class test { > var __yoyoman; > private var yoyoman; > } > > Or even simpler, what if just var __yoyoman was declared? Would the access > fail even though it was public? Depends on the implementation of the private. I proposed it the Python way: rewrite the variable name to something else, and when you encounter an access request, go get the actual attribute: i.e. class Foo { var $__myprivate; function getIt() { return $this->__myprivate;} } what should happen? when the class is parsed, don't add `__myprivate' as an attribute, but add instead _Foo__myprivate. Then apply a simple rule when the user wants `__myprivate': is the access within a class method? yes - get _Foo__myprivate, else we have an access violation. e.g. $this->__myprivate is actually translated into something like $this->_Foo__myprivate. you need the class name to reconstruct the real attribute, and you will always have it when within a method (I guess :) Same goes with `private' keyword, but there is some glitch here. Andi pointed you would need to know the class at compile time, so to check if $this->yoyoman' is private or not, but with this __' hack you just look at the variable name: does it start with 2 x _ ? deny access if not in a method scope. -- teodor