PHP 4.0 Bug #8305 Updated: RETURNTRANSFER output not properly send back to variable
| From: | sterling@php.net | Date: | Mon, 01 Jan 2001 20:50:19 +0000 |
| Subject: | PHP 4.0 Bug #8305 Updated: RETURNTRANSFER output not properly send back to variable | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-42553@lists.php.net to get a copy of this message | ||
ID: 8305
Updated by: sterling
Reported By: emilebosch@hotmail.com
Old-Status: Open
Status: Closed
Bug Type: cURL related
Assigned To:
Comments:
Fixed in CVS (Once CVS comes back up that is ;-).
Previous Comments:
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[2000-12-17 20:16:03] emilebosch@hotmail.com
In this code the output has to be send back to $result, it works correctly except for the last
character of the "localhost/curl/curl_feed.php" document, its not being outputted whils
when using not the RETURNTRANSFER option the output is being output correctly: IE:
localhost/curl/curl_feed.php outputs:
WITHOUT : curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
this is a test
WITH : curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
this is a tes
*NoTice* The last character is missing. this can't be good :((
I would aprreciate it highly if someone could take a look at this :-)
Kind regards,
Emile Bosch
<?
dl("php_curl.dll");
$ch = curl_init ("localhost/curl/curl_feed.php");
curl_setopt($ch,CURLOPT_POST,1);
curl_setopt($ch,CURLOPT_POSTFIELDS,"action=getUser");
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
echo $result = curl_exec ($ch);
curl_close ($ch);
?>
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Full Bug description available at: http://bugs.php.net/?id=8305