Bug #13315 Updated: problem with function definitions

ID: 13315 Updated by: hholzgra Reported By: php@altemachtige.reageerttochniet.nl Status: Bogus Bug Type: *General Issues Operating System: WIN98/APACHE1.3.19 PHP Version: 4.0.4pl1 New Comment: no way, default values are evaluated at compile time and there is no $foo set at all as the program didn't start to run by that time what you want to do is something like function showvar ( $bar = NULL ) { if ( $bar === NULL ) { $bar = $GLOBALS['foo']; } echo $bar; } Previous Comments: ------------------------------------------------------------------------ [2001-09-15 05:43:00] php@altemachtige.reageerttochniet.nl why is that? I really need this:( Will a later version of php support constructions like this? ------------------------------------------------------------------------ [2001-09-15 05:28:13] mfischer@php.net Shouldn't. Default values must be constant expressions. Not a bug, bogusified. - Markus ------------------------------------------------------------------------ [2001-09-15 05:11:56] php@altemachtige.reageerttochniet.nl <?php $foo = 'foo'; function showvar( $bar = $foo ) { //global $foo //doesn't work either echo $bar; } showvar(); showvar('bar'); ?> gives me a parse error on line 3:( also: <?php $foo = 'foo'; function returnvar() { global $foo; return $foo; } function whatisvar( $bar = returnvar() ) { echo $bar; } ?> gives me this: Parse error: parse error, expecting `')'' in c:/path/to/script/test.php on line 9 Should work, shouldn't it? ------------------------------------------------------------------------ Edit this bug report at http://bugs.php.net/?id=13315&edit=1