RE: [PHP] Passing variable to new page and pulling the rest of in fo from database
| From: | Scott Hurring | Date: | Wed, 05 Jun 2002 20:30:52 +0000 |
| Subject: | RE: [PHP] Passing variable to new page and pulling the rest of in fo from database | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-100788@lists.php.net to get a copy of this message | ||
Ahhh! quote that ID number before using it in a query! :)
// for mysql
mysql_quote($_GET['ID']);
---
Scott Hurring
Systems Programmer
EAC Corporation
ScottH@eac.com
Voice: 201-462-2149
Fax: 201-288-1515
> -----Original Message-----
> From: 1LT John W. Holmes [mailto:holmes072000@charter.net]
> Sent: Wednesday, June 05, 2002 4:29 PM
> To: Igor Portnoy; php-general@lists.php.net
> Subject: Re: [PHP] Passing variable to new page and pulling
> the rest of
> info from database
>
>
> SELECT * FROM table WHERE ID = $_GET['ID']
>
> Then create a page to display all of that information. Look
> at the mysql
> functions and learn some PHP. We can't help you without
> knowing what's in
> your table and how you want it displayed, etc...
>
> So keep learning and reading and you'll figure out how to do it. Your
> question is way to broad for any help...
>
> ---John Holmes...
>
> ----- Original Message -----
> From: "Igor Portnoy" <igor@gibsonusa.com>
> To: <php-general@lists.php.net>
> Sent: Wednesday, June 05, 2002 2:40 PM
> Subject: [PHP] Passing variable to new page and pulling the
> rest of info
> from database
>
>
> Hello,
>
>
>
> I am passing a variable to the new page, when user clicks on the link.
> Something like that:
>
> <a href="showimage.php?ID=38"><img
> src="/some/image.jpg"></a>
>
>
>
> How can I extract all other information out of my database for that ID
> in the next page (showimage.php)?
>
>
>
> Thanks
>
>
>
>
>
>
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