RE: [PHP] Passing variable to new page and pulling the rest of in fo from database
| From: | Scott Hurring | Date: | Wed, 05 Jun 2002 21:29:35 +0000 |
| Subject: | RE: [PHP] Passing variable to new page and pulling the rest of in fo from database | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-100811@lists.php.net to get a copy of this message | ||
Sorry, i meant: mysql_escape_string( $value )
I use a class to handle accessing the database, and i
named the function $db->quote(...); i keep forgetting
that the actual function call that the class is making ;-)
And yes, validating that it's an integer works also,
but even after pregging vars to all hell and back to
verify contents, i still quote. i'm paranoid. :)
---
Scott Hurring
Systems Programmer
EAC Corporation
ScottH@eac.com
Voice: 201-462-2149
Fax: 201-288-1515
> -----Original Message-----
> From: 1LT John W. Holmes [mailto:holmes072000@charter.net]
> Sent: Wednesday, June 05, 2002 5:10 PM
> To: Scott Hurring; Php-General (E-mail)
> Subject: Re: [PHP] Passing variable to new page and pulling
> the rest of
> info from database
>
>
> Or simply just validate it's an integer, like it should be,
> like you would
> do with any user input...
>
> There is no mysql_quote() function...or am I missing something?
>
> ---John Holmes...
>
> ----- Original Message -----
> From: "Scott Hurring" <scott@eacnet.com>
> To: "Php-General (E-mail)" <php-general@lists.php.net>
> Sent: Wednesday, June 05, 2002 4:30 PM
> Subject: RE: [PHP] Passing variable to new page and pulling
> the rest of info
> from database
>
>
> > Ahhh! quote that ID number before using it in a query! :)
> >
> > // for mysql
> > mysql_quote($_GET['ID']);
> >
> > ---
> > Scott Hurring
> > Systems Programmer
> > EAC Corporation
> > ScottH@eac.com
> > Voice: 201-462-2149
> > Fax: 201-288-1515
> >
> > > -----Original Message-----
> > > From: 1LT John W. Holmes [mailto:holmes072000@charter.net]
> > > Sent: Wednesday, June 05, 2002 4:29 PM
> > > To: Igor Portnoy; php-general@lists.php.net
> > > Subject: Re: [PHP] Passing variable to new page and pulling
> > > the rest of
> > > info from database
> > >
> > >
> > > SELECT * FROM table WHERE ID = $_GET['ID']
> > >
> > > Then create a page to display all of that information. Look
> > > at the mysql
> > > functions and learn some PHP. We can't help you without
> > > knowing what's in
> > > your table and how you want it displayed, etc...
> > >
> > > So keep learning and reading and you'll figure out how to
> do it. Your
> > > question is way to broad for any help...
> > >
> > > ---John Holmes...
> > >
> > > ----- Original Message -----
> > > From: "Igor Portnoy" <igor@gibsonusa.com>
> > > To: <php-general@lists.php.net>
> > > Sent: Wednesday, June 05, 2002 2:40 PM
> > > Subject: [PHP] Passing variable to new page and pulling the
> > > rest of info
> > > from database
> > >
> > >
> > > Hello,
> > >
> > >
> > >
> > > I am passing a variable to the new page, when user clicks
> on the link.
> > > Something like that:
> > >
> > > <a href="showimage.php?ID=38"><img
> > > src="/some/image.jpg"></a>
> > >
> > >
> > >
> > > How can I extract all other information out of my
> database for that ID
> > > in the next page (showimage.php)?
> > >
> > >
> > >
> > > Thanks
> > >
> > >
> > >
> > >
> > >
> > >
> > > --
> > > PHP General Mailing List (http://www.php.net/)
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> > >
> >
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>