RE: [PHP] question about ? :
| From: | Martin Towell | Date: | Fri, 14 Jun 2002 00:22:19 +0000 |
| Subject: | RE: [PHP] question about ? : | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-102113@lists.php.net to get a copy of this message | ||
Lee - I would bracket anyway, just to make sure, and to make it clear to the
coder what's happening
Miguel - that's fine when using two operators that have different
precedence, but all three operators are ?:
-----Original Message-----
From: Miguel Cruz [mailto:mnc@stoic.net]
Sent: Friday, June 14, 2002 10:13 AM
To: Lee Doolan
Cc: php-general@lists.php.net
Subject: Re: [PHP] question about ? :
On 13 Jun 2002, Lee Doolan wrote:
> the arrays below have dates like
> dateA= array( 0=> "03", 1=> "22", 2=> "02")
>
> for 22march2002.
>
> why does this work:
>
> $retval= ($dateA[2] != $dateB[2])
> ? strcmp($dateA[2], $dateB[2])
> : (($dateA[0] != $dateB[0])
> ? strcmp($dateA[0], $dateB[0])
> : (($dateA[1] != $dateB[1])
> ? strcmp($dateA[1], $dateB[1])
> : 0));
>
>
> but not this:
>
> $retval= ($dateA[2] != $dateB[2])
> ? strcmp($dateA[2], $dateB[2])
> : ($dateA[0] != $dateB[0])
> ? strcmp($dateA[0], $dateB[0])
> : ($dateA[1] != $dateB[1])
> ? strcmp($dateA[1], $dateB[1])
> : 0;
Why does this:
$x = 3 + 5 * 7;
produce different results from this:
$x = (3 + 5) * 7;
?
miguel
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