RE: question about ? :

> -----Original Message----- > From: Joel Boonstra [mailto:jboonstra@gospelcom.net] > Sent: 19 June 2002 14:00 > > > OK, try this: why does > > > > $x = 3 + 5 - 7; > > > > produce different results from > > > > $x = 3 + (5 - 7); > > Really? It shouldn't produce different results for you -- they should > both evaluate to '1'. Jeez, you're right! That was dumb!! Somehow I suffered a brain-wibble that managed to calculate 5-7 as +2 rather than -2. As I studied maths all the way up to 1st year at university -- and do understand the rules of precedence and associativity, honest, boss -- I really shouldn't have made that kind of basic error. Still, the principle I was trying to illustrate is still good, even if my example was complete codswallop, so let's try again. Why does: $x = 9 - 5 + 3; // 7 produce a different result from: $x = 9 - (5 + 3); // 1 Cheers! Mike --------------------------------------------------------------------- Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: m.ford@lmu.ac.uk Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211