Re: printf()

Well I figured out a solution. Using a combination of explode() to create an array from $bar, check to see if $bar is an array and feed the array to vprintf().... Gerard Samuel wrote:

Im trying to make a dynamic printf(). By that I mean -> function this($foo, $bar) { if (strlen($bar) == '0') {

        print($foo);

} else {

       printf($foo, $bar);

} } Now it works if there is one argument passed, but it doesn't when there is more than one. $str = 'should'; this('This %s work', $str); // work $str = 'is, a'; this('This %s just %s test', $str); // doesn't work So I guess, arguments passed to it has to be physical arguments, and not represented in a string. Am I banging my head on a wall with this?? Thanks

-- Gerard Samuel http://www.trini0.org:81/ http://dev.trini0.org:81/