Re: substr?

I'm confused, are you trying to compare the first three characters of the string? If you are I think what you want is: substr($string,0,3); Adam Voigt adam.voigt@cryptocomm.com On Mon, 2002-06-17 at 04:28, Chris Knipe wrote: > Hi all, > > Is this right? It seems to me that substr is working in reverse? > > $string = "1234567890"; // Always numerical, always 10 chars. > if (!substr($string, 0, -7) == "083") { > echo "not 083\n"; > } else { > // Exists here. > echo "is 083\n"; > } > > Due to the reverse if, shouldn't it exit not 083? I'd just like > to get some clarity on this, allot of my work depends on validating these > numbers *correctly*.... Basically, I want to see if the first three > characters is 072, 073, 082, 083, or 084. If not, the $string must be > discarded. > > I've also tried if(substr($string, 0, -7) != "083"), but that also doesn't > work.... ereg(*) also doesn't seem to be able to search for patterns only on > the beginning of a string, so even if I wanted to use a ereg expression, I'd > have to cut the first 3 chars from the string with substr first? > > How can / should I validate these numbers? > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >