Re: Displaying PHP-File

Martin Thoma wrote:

.. sorry, I think you didn't quite get the point. The page with HTML and

Uh oh, that again. :)

php-code is called "myform.php4" and works perfectly when calling it directly (for example typing "myform.php4 into the url-field of the browser). Now I want to do the following: Antoher script is called, and when this other script detects an error, "myform.php4" should be read-in as a file, modified (for example displaying "There is an error in field ..." somewhere) and then be printed out.

How about something like: <?php if($processed) { /* Verify that all required fields were processed. */ if(!SomeFunctionForCheckingFields($fields)) {

     /* if fields are blank */
     include 'myform.php4';

} else {

     /* if they're ok, go somewhere else */
     header("Location: http://www.server.com/success.php");
     exit; /* probably redundant */

} } /* include form if we're still here, or just got here */ include 'form.php'; /* submit button is named 'processed' */ ?>

When printing out the page, the HTML-Code is shown, but the form is gone because the php-part is not execute. How can I avoid this ? (if possible without using redirection because I got a lot of redirections in my code and this one redirection would make it much more complicated).

Brian