Re: php: assignment operator

> That's the case if strlen($counter) is 1. If it were more, you'd see > multiple image tags in there. > > --Dan ................................ Thanks Dan. I tried an example with the number 3 replacing the number 1 ....................... $image_src=$image_dir. "/" .substr($counter, $i, 3) . ".jpg"; .......................... and the script works o.k. so I couldn't see the difference. Also, I understand that the difference is that .= appends onto the value of the variable whereas = replaces the value of the variable. However, in examples such as: $a="This is a"; $a.="test"; echo $a; // displays This is a test There is a variable that has previously existed with a value In the script that I supplied, the variable: $image_tag_src did not hold any value until the line with the .= operator so I am still baffled. Many thanks. TR ............................................... Analysis & Solutions <danielc@analysisandsolutions.com> wrote in message news:20020807004145.GA29909@panix.com... > On Tue, Aug 06, 2002 at 07:54:47PM -0500, Anthony Ritter wrote: > > > > for($i=0; $i<strlen($counter); $i++) > > { > > $image_src=$image_dir. "/" .substr($counter, $i, 1) . ".jpg"; > > $image_tag_src.="<IMG SRC=\"$image_src\" > > BORDER=\"0\">"; // assignment > > operator .= > > } > > See > http://www.php.net/manual/en/language.operators.assignment.php. > > .= appends the text to the right of the operator to the end of the > variable on the left side of the operator. > > Therefore, $image_tag_src will be one long string containing several "<img > src..." in it, one for each time the loop executes. > > Be careful. Before using this operator, make sure you manually set the > variable to something, such as: > > $image_tag_src = ''; > > before starting in order to avoid people hacking your code by putting > nasty text in the $image_tag_src variable. > > > > If I was to assign the html string to the variable $image_tag_src without > > the .= and insert a =, the script continues to run fine since $image_src > > still contiunes to hold the value of > > $image_dir. "/" .substr($counter, $i, 1) . ".jpg"; > > That's the case if strlen($counter) is 1. If it were more, you'd see > multiple image tags in there. > > --Dan > > -- > PHP classes that make web design easier > SQL Solution | Layout Solution | Form Solution > sqlsolution.info | layoutsolution.info | formsolution.info > T H E A N A L Y S I S A N D S O L U T I O N S C O M P A N Y > 4015 7 Av #4AJ, Brooklyn NY v: 718-854-0335 f: 718-854-0409