Re: php: assignment operator

On Wednesday, August 7, 2002, Anthony Ritter wrote: [Not sure what .= does] > The complete script: > <? > $counter_file="./counter.txt"; > $image_dir= "./images"; > if(!($fp=fopen($counter_file, "r")))die("Couldn't open the file"); > $counter=(int)fread($fp, 20); > fclose($fp); > $counter++; > for($i=0; $i<strlen($counter); $i++) > { > $image_src=$image_dir. "/" .substr($counter, $i, 1) . ".jpg"; > $image_tag_src.="<IMG SRC=\"$image_src\" BORDER=\"0\">"; > } > echo "You are visitor $image_tag_src"; > $fp=fopen($counter_file, "w"); > fwrite($fp,$counter); > fclose($fp); ?>> .= means add to the value of. So in this case, there's an image file for each number - 0-9, so if your counter value is 24, you'll need two images - a two and a four. Similarly, if your counter value was 123, you'd want three images - a one, a two and a three. The for loop in the code above loops round once for each digit in $counter (strlen($counter)), and _adds_ the HTML for the image tag to the current value of $image_tag_src. I hope that makes things a little clearer (and that I've understood your problem correctly!) -- Tim Fountain (tim@tfountain.co.uk) http://www.tfountain.co.uk/