strange shell script, #!/usr/local/bin/php doesnt work, php file.php does...

Im having a strange problem... if i run a php type shell script with the format: commandline> php -q somefile.php3 commandline> Set-Cookie: YA_SESSION_ID=4cb6bcbef9167aff1a2d314ec01ba2fd; expires=Tuesday, 11- Jul-00 21:57:57 GMT . . . It works perfect... However running the same somefile as commandline> ./somefile.php3 with the #!/usr/local/bin/php -q option at the top of somefile.php3 yields me: php: invalid option -- Usage: php [-q] [-h] [-s] [-v] [-i] [-f <file>] | {<file> [args...]} -q Quiet-mode. Suppress HTTP Header output. -s Display colour syntax highlighted source. -f<file> Parse <file>. Implies `-q' -v Version number -p Pretokenize a script (creates a .php3p file) -e Execute a pretokenized (.php3p) script -c<path> Look for php3.ini file in this directory -i PHP information -h This help ive tried numerous things to no help...! this is running linux 2.2.15 php 3.0.16 Any ideas? as a last resort i can run everything ias php filename.php3 but preferred the #!/... method. Thanks!