RE: [PHP] mysql password function

From: Date: Mon, 23 Sep 2002 01:49:08 +0000
Subject: RE: [PHP] mysql password function
References: 1  Groups: php.general 
Request: Send a blank email to php-general+get-117222@lists.php.net to get a copy of this message
Use this: $result = mysql_query("SELECT PASSWORD(" . $_POST['password'] . ")"); $password = mysql_result($result,0); or just use mysql_fetch_row() or AS in your query so you don't have to recreate that complex column name. ---John Holmes... > -----Original Message----- > From: Murat Ö. [mailto:murat_inf@yahoo.com] > Sent: Sunday, September 22, 2002 9:33 AM > To: php-general@lists.php.net > Subject: [PHP] mysql password function > > hi, > i want to encode a string that users enter with mysql password function. > but > sometimes this code works sometimes don't. mysql warns me: > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL > result > resource in ........ > > the code is: > > $result=mysql_query("select password(".$_POST['password'].")"); > while ($p = mysql_fetch_array($result, MYSQL_ASSOC)): > $pswrd=$p['password('.$_POST['password'].')']; > endwhile; > > thanks... > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php

« previous php.general (#117222) next »