RE: [PHP] Array question
| From: | Mark Roedel | Date: | Wed, 16 Aug 2000 17:06:27 +0000 |
| Subject: | RE: [PHP] Array question | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-12061@lists.php.net to get a copy of this message | ||
> -----Original Message-----
> From: Paulson, Joseph V. "Jay" [mailto:jay.paulson@viatel.com]
> Sent: Wednesday, August 16, 2000 11:29 AM
> To: php-general
> Subject: [PHP] Array question
>
>
> I have a quick question about declaring an array. Below is the
> code snippet that I am dealing with. What happens when i traverse
> the $select["options"] position I only get the last two positions
> of the $selectOptions array. Obviously, I need it to traverse all
> the positions in the $select["options"] array. I don't have a clue
> as to why this is only traversing the last two positions (no matter
> how many elements are in the array), but any help would be greatly
> appreciated!
>
> $selectOptions = array("label"=>";lkj",
> "value"=>"l;kj;",
> "label"=>"canada",
> "value"=>"Canada", "label"=>"usa",
> "value"=>"USA");
(Or, translated out into a longer form)
$selectOptions["label"] = ";lkj";
$selectOptions["value"] = "l;kj";
$selectOptions["label"] = "canada";
$selectOptions["value"] = "Canada";
$selectOptions["label"] = "usa";
$selectOptions["value"] = "USA";
Can you see from this what might be causing your problem?
---
Mark Roedel | "Blessed is he who has learned to laugh
Systems Programmer | at himself, for he shall never cease
LeTourneau University | to be entertained."
Longview, Texas, USA | -- John Powell