Re: Array question

In article <F99F3F7C7049D211BC700008C7B1F0900759AB4F@texas.econophone.com>, jay.paulson@viatel.com ("Paulson, Joseph V. \"Jay\"") wrote: > hello everyone! > > I have a quick question about declaring an array. Below is the code > snippet that I am dealing with. What happens when i traverse the > $select["options"] position I only get the last two positions of the > $selectOptions array. Obviously, I need it to traverse all the positions > in the $select["options"] array. I don't have a clue as to why this is > only traversing the last two positions (no matter how many elements are > in the array), but any help would be greatly appreciated! > > $selectOptions = array("label"=>";lkj", > "value"=>"l;kj;", > "label"=>"canada", > "value"=>"Canada", "label"=>"usa", > "value"=>"USA"); > Your array only has two hash keys: 'label' and 'value'. Your assignments of valus of 'canada' and 'usa' for the 'label' key simply replace the value of the previously defined hash element. Sounds like you need something more like: $selectOptions["label"][0] = ";lkj"; $selectOptions["label"][1] = "l;kj"; $selectOptions["label"][2] = "canada"; etc... Jeff $select = array("type"=>"select", "name"=>"select", "value"=>"canada", > "options"=>$selectOptions); > > reset($select["options"]); while (list($key, $value) = > each($select["options"])){ > $debugMsg .= "select[\"".$key."\"] = > ".$value."<br>\n"; > } > echo $debugMsg; > > Thanks, Jay Paulson > > ps I am running PHP version 3.0.15 >