Re: counting chars, if statement
| From: | Martin | Date: | Thu, 17 Aug 2000 09:17:49 +0000 |
| Subject: | Re: counting chars, if statement | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-12187@lists.php.net to get a copy of this message | ||
Hm, it works perfectly on my computer. Any other things around that could be
disturbing ?
Martin
Anders Dannberg wrote:
> Hello!
> I have a small problem with the if-statement on the below example. Why
> doesn't this work? I've also tried ($out != "5") but it won't display
> anything.
> Also tried "==", "<", ">".... What am i doing wrong?
>
> $string = "abcdefghijkl";
> $out = strlen($string);
> if ($out != 5) { echo "... value is not 5";
> }
> Thanks in advance.
> Anders
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net
> For additional commands, e-mail: php-general-help@lists.php.net
> To contact the list administrators, e-mail: php-list-admin@lists.php.net