Re: counting chars, if statement
| From: | Martin | Date: | Thu, 17 Aug 2000 09:25:36 +0000 |
| Subject: | Re: counting chars, if statement | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-12189@lists.php.net to get a copy of this message | ||
Marcel Schwarz wrote:
> > Hello!
> > I have a small problem with the if-statement on the below example. Why
> > doesn't this work? I've also tried ($out != "5") but it won't
> > display
> > anything.
> > Also tried "==", "<", ">".... What am i doing wrong?
> >
> > $string = "abcdefghijkl";
> > $out = strlen($string);
> > if ($out != 5) { echo "... value is not 5"; }
>
> what result did you expect ?
>
> in this example your program will echo "... value is not 5"
> because $out=12.
>
Hi Marcel,
I think the point it that it should of course output "... value is not 5",
but in fact it's outputting nothing and that's the problem.
Greetings (und Grüße aus Darmstadt ;-))
Martin
>
> Marcel.
>
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