Re: $_SESSIONS and printing off..

Thanks, But then another question; if (isset($_SESSION['username']) && !empty($_SESSION['username'])) { > echo 'Welcome '.$_SESSION['username'].', you are still logged > in.'; I want also checked if the level of authentication = 2; for example User Frank = level 1 User Rich = level 2 I've set $_SESSION['level'] to 2 but how can i check that with the above line? Thanks for your help, Frank ----- Original Message ----- From: "Rich Gray" <rich@f1central.net> To: "Frank Keessen" <fkeessen@planet.nl>; <php-general@lists.php.net> Sent: Tuesday, February 18, 2003 11:53 AM Subject: RE: [PHP] $_SESSIONS and printing off.. > Er... well I've seen a lot worse code than that but maybe you could use ... > > if (isset($_SESSION['username']) && !empty($_SESSION['username'])) > { > echo 'Welcome '.$_SESSION['username'].', you are still logged > in.'; > } > else { > header... etc etc > } > > Rich > > -----Original Message----- > > From: Frank Keessen [mailto:fkeessen@planet.nl] > > Sent: 18 February 2003 09:00 > > To: php-general@lists.php.net > > Subject: [PHP] $_SESSIONS and printing off.. > > > > > > Hi All, > > > > I'm a little bit confused and it's maybe a newbie question but > > maybe you can help me out; > > > > A user is login in and after username password check it will > > redirects to this page > > > > <?php > > session_start(); > > if (isset($_SESSION['username'])){ > > $username = $_SESSION['username']; > > echo 'Welcome, you are still loged in.'; > > echo $username; > > } > > else{ > > header ( "Location: login.htm" ); > > } > > ?> > > > > Question is; is this the way to print of his username? > > > > $username = $_SESSION['username']; > > Echo $username > > > > Or has anyone some alternatives.. > > > > This is working o.k. but in my opinion it's a little bit quick and dirty? > > > > Thanks for the comments and suggestions! > > > > Frank > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >