Re: $_SESSIONS and printing off..

Uh, sorry for the bad explanation Rich.. Again; <?php session_start(); if (isset($_SESSION['username']) && !empty($_SESSION['username'])){ echo 'Welcome '.$_SESSION['username'].', you are still logged in.'; echo $_SESSION['woonplaats']; } else{ header ( "Location: login.htm" ); } ?> This is working fine. But i've set $_SESSION['level'] to value 2 (that's done in the php file that calls this one). Now i want the above code to check for the level and if is not equal to two than go to the else (back to login.htm) statement.. better explained??? ;> Thanks, Frank ----- Original Message ----- From: "Rich Gray" <rich@f1central.net> To: "Frank Keessen" <fkeessen@planet.nl>; <php-general@lists.php.net> Sent: Tuesday, February 18, 2003 1:25 PM Subject: RE: [PHP] $_SESSIONS and printing off.. > Um... how about... > > echo 'Welcome '.$_SESSION['username'].', you are still logged in and > your > authentication level is '.(isset($_SESSION['level']) ? > $_SESSION['level'] : > 'unknown'); > > Or am I missing something here? > > Rich > > > -----Original Message----- > > From: Frank Keessen [mailto:fkeessen@planet.nl] > > Sent: 18 February 2003 12:15 > > To: Rich Gray; php-general@lists.php.net > > Subject: Re: [PHP] $_SESSIONS and printing off.. > > > > > > Thanks, > > > > But then another question; > > > > if (isset($_SESSION['username']) && > > !empty($_SESSION['username'])) { > > > echo 'Welcome '.$_SESSION['username'].', you are still > > > logged in.'; > > > > > > I want also checked if the level of authentication = 2; for example > > User Frank = level 1 > > User Rich = level 2 > > > > I've set $_SESSION['level'] to 2 but how can i check that with the above > > line? > > > > Thanks for your help, > > > > Frank > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >