Re: Displaying a file

Same way <img src='image.php?file=myimage.gif' /> image.php would do simular things to what view.php does in the script below. Justin on 10/03/03 2:07 PM, Mark Tehara (mark@crushme.dyndns.org) wrote: > On that note, how would i load an image from outside the document root? > > > > ----- Original Message ----- > From: "Justin French" <justin@indent.com.au> > To: "Todd Cary" <todd@aristesoftware.com>; <php-general@lists.php.net> > Sent: Monday, March 10, 2003 4:06 PM > Subject: Re: [PHP] Displaying a file > > >> Change your link to something like: >> >> <a href="view.php?file=raceschedule.pdf" ...>...</a> >> >> view.php will NOT be a "HTML page" -- it will be responsible for: >> >> a) some conditional stuff, like checking for a logged in user >> b) output an appropriate header for the file type >> c) pass through the actual file contents >> >> >> You would actually want to store the target files outside the doc root, or >> forbid apache to serve them directly over http. >> >> There's a decent article here: >> http://www.zend.com/zend/trick/tricks-august-2001.php >> >> >> Justin French >> >> >> >> on 10/03/03 1:17 PM, Todd Cary (todd@aristesoftware.com) wrote: >> >>> I want to display a file under program control in the same manner as one >>> would with using an >a> tag e.g. >>> >>> Click <a href="files/raceschedule.pdf" Name="Race Schedule" >>> Target="_blank">here</a> to open the Race Schedule >>> >>> In other words, if certain conditions are met, then I want to display >>> the file. What is the best way to do that? >>> >>> Many thanks..... >>> >>> Todd >> >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php >> >> > >