Re: Displaying a file

OK! This makes sense. What is the syntax to do b) output an appropriate header for the file type c) pass through the actual file contents if I were doing an HTML file - if I were doing a PDF file? Todd Justin French wrote:

Same way <img src='image.php?file=myimage.gif' /> image.php would do simular things to what view.php does in the script below. Justin on 10/03/03 2:07 PM, Mark Tehara (mark@crushme.dyndns.org) wrote:

On that note, how would i load an image from outside the document root? ----- Original Message ----- From: "Justin French" <justin@indent.com.au> To: "Todd Cary" <todd@aristesoftware.com>; <php-general@lists.php.net> Sent: Monday, March 10, 2003 4:06 PM Subject: Re: [PHP] Displaying a file

Change your link to something like: <a href="view.php?file=raceschedule.pdf" ...>...</a> view.php will NOT be a "HTML page" -- it will be responsible for: a) some conditional stuff, like checking for a logged in user b) output an appropriate header for the file type c) pass through the actual file contents You would actually want to store the target files outside the doc root, or forbid apache to serve them directly over http. There's a decent article here: http://www.zend.com/zend/trick/tricks-august-2001.php Justin French on 10/03/03 1:17 PM, Todd Cary (todd@aristesoftware.com) wrote:

I want to display a file under program control in the same manner as one would with using an >a> tag e.g. Click <a href="files/raceschedule.pdf" Name="Race Schedule" Target="_blank">here</a> to open the Race Schedule In other words, if certain conditions are met, then I want to display the file. What is the best way to do that? Many thanks..... Todd

-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

-- Ariste Software, Petaluma, CA 94952 \n info@aristesoftware.com