Re: If else.. display no picture..

I would help if you told us which line the error was on On Sat, 5 Apr 2003 fkeessen@planet.nl wrote: > Hi, > > I'm trying to do the following.. When $stadpict is filled in it must display the picture > (only the path to the picture is stored in Mysql). But when the string ($stadpict) is empty then it > must not display the picture (and also not display a box with a red cross in it (can't display > picture! ;>). The only thing i'm getting is an error message... > > Parse error: parse error, unexpected T_STRING, expecting ',' or ';' > > Code; > <? > // includes > include("../conf/config.php"); > > // open database connection > $connection = mysql_connect($host, $user, $pass) or die ("Unable to connect!"); > > // select database > mysql_select_db($db) or die ("Unable to select database!"); > $stedenid=$_GET['stedenid']; > > // generate and execute query > $query2 = "SELECT stedenid, naamstad, stadomschrijvk, stadpict FROM steden WHERE stedenid > = $stedenid"; > $result2 = mysql_query($query2) or die ("Error in query: $query2. " . mysql_error()); > $row2 = mysql_fetch_object($result2); > if (mysql_num_rows($result2) > 0) > { > ?> > > <font class="bold"><? echo $row2->naamstad; ?> </font> > <br><br><? echo $row2->stadpict; > ?> > > </td> > </tr> > </table> > <table cellspacing="0" width="405" cellpadding="0" > border="0"> > <tr style="padding-top:10"> > <td width="139" valign="top" style="padding-left:20"> > <? > while($row->$stadpict > 0) > { > ?> > <img src="../steden/images/<? echo $row->stadpict; ?>" > border="0" width="108" height="160" alt=""></td> > <? > } > ?> > <td width="266" valign="top" > style="padding-right:10;padding-left:10"><? echo $row2->stadomschrijvk; > } > else > > { > Echo Geen informatie beschikbaar; > } > ?> > > > Thanks for helping me out! > > Frank > >