RE: [PHP] If else.. display no picture..
| From: | John W. Holmes | Date: | Sun, 06 Apr 2003 21:28:45 +0000 |
| Subject: | RE: [PHP] If else.. display no picture.. | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-142615@lists.php.net to get a copy of this message | ||
PUT QUOTES AROUND YOUR STRING. THIS HAS ALREADY BEEN POINTED OUT A
COUPLE TIMES.
echo "Geen informatie beschikbaar";
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
> -----Original Message-----
> From: Frank Keessen [mailto:fkeessen@planet.nl]
> Sent: Sunday, April 06, 2003 4:39 PM
> To: Rasmus Lerdorf
> Cc: php-general@lists.php.net
> Subject: Re: [PHP] If else.. display no picture..
>
> Hi,
>
> Sorry;
>
> Parse error: parse error, unexpected T_STRING, expecting ',' or ';' in
> /home/.sites/95/site92/web/steden/steden.php on line 125
>
> This is line 125; echo Geen informatie beschikbaar;
>
> Regards,
>
> Frank
>
> ----- Original Message -----
> From: "Rasmus Lerdorf" <rasmus@lerdorf.com>
> To: <fkeessen@planet.nl>
> Cc: <php-general@lists.php.net>
> Sent: Saturday, April 05, 2003 5:54 PM
> Subject: Re: [PHP] If else.. display no picture..
>
>
> > I would help if you told us which line the error was on
> >
> > On Sat, 5 Apr 2003 fkeessen@planet.nl wrote:
> >
> > > Hi,
> > >
> > > I'm trying to do the following.. When $stadpict is filled in it
must
> display the picture (only the path to the picture is stored in Mysql).
But
> when the string ($stadpict) is empty then it must not display the
picture
> (and also not display a box with a red cross in it (can't display
picture!
> ;>). The only thing i'm getting is an error message...
> > >
> > > Parse error: parse error, unexpected T_STRING, expecting ',' or
';'
> > >
> > > Code;
> > > <?
> > > // includes
> > > include("../conf/config.php");
> > >
> > > // open database connection
> > > $connection = mysql_connect($host, $user, $pass) or die ("Unable
to
> connect!");
> > >
> > > // select database
> > > mysql_select_db($db) or die ("Unable to select database!");
> > > $stedenid=$_GET['stedenid'];
> > >
> > > // generate and execute query
> > > $query2 = "SELECT stedenid, naamstad, stadomschrijvk, stadpict
FROM
> steden WHERE stedenid = $stedenid";
> > > $result2 = mysql_query($query2) or die ("Error in query: $query2.
" .
> mysql_error());
> > > $row2 = mysql_fetch_object($result2);
> > > if (mysql_num_rows($result2) > 0)
> > > {
> > > ?>
> > >
> > > <font class="bold"><? echo $row2->naamstad; ?> </font>
> > > <br><br><? echo $row2->stadpict;
> > > ?>
> > >
> > > </td>
> > > </tr>
> > > </table>
> > > <table cellspacing="0" width="405" cellpadding="0"
> > > border="0">
> > > <tr style="padding-top:10">
> > > <td width="139" valign="top"
> > > style="padding-left:20">
> > > <?
> > > while($row->$stadpict > 0)
> > > {
> > > ?>
> > > <img src="../steden/images/<? echo $row->stadpict; ?>"
> > > border="0"
> width="108" height="160" alt=""></td>
> > > <?
> > > }
> > > ?>
> > > <td width="266" valign="top"
> > > style="padding-right:10;padding-
> left:10"><?
> echo $row2->stadomschrijvk;
> > > }
> > > else
> > >
> > > {
> > > echo Geen informatie beschikbaar;
> > > }
> > > ?>
> > >
> > >
> > > Thanks for helping me out!
> > >
> > > Frank
> > >
> > >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
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> >
>
>
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