RE: [PHP] How do I insert PHP script into existing script? Php script within script?

From: Date: Wed, 09 Apr 2003 21:04:25 +0000
Subject: RE: [PHP] How do I insert PHP script into existing script? Php script within script?
References: 1  Groups: php.general 
Request: Send a blank email to php-general+get-143209@lists.php.net to get a copy of this message
Yes, server is told to treat .html files as .php The reason I have such a screwy setup is because I have no time or money to redo everything in PHP (I got to learn it first). I know html well, I get php to work for me throuhg free scripts, that is where my experience with Php ends... Quoting Jennifer Goodie <goodie@apollointeractive.com>: > Is "whatever.html" going to go through the PHP parser? Treating the .html > extension as PHP is not standard and the server has to be told to do it. > > > -----Original Message----- > > From: Apollo (Carmel Entertainment) [mailto:lists@carmelme.com] > > Sent: Wednesday, April 09, 2003 1:58 PM > > To: php-general@lists.php.net > > Subject: Re: [PHP] How do I insert PHP script into existing script? Php > > script within script? > > > > > > So let me see if I get you right. > > This is my html page on the server is named whatever.html > > page contains: > > <?php > > $db = mysql_connect("host", "username", "password"); > > if( !$db ) > > { > > die("Error connecting to the Server"); > > exit; > > } > > $result = mysql_select_db("www", $db); > > if( !$result ) > > { > > die("Error selecting Database"); > > exit; > > } > > > > ?> > > <?php > > $query = "SELECT > > * > > FROM > > html > > WHERE > > html.id='1'"; > > $result = mysql_query($query,$db); > > if( !$result ) > > { > > die("No record"); > > } > > { > > $code = mysql_result($result,$row,"code"); > > echo "$code"; > > } > > mysql_free_result($result); > > mysql_close(); > > ?> > > > > Then when you go into database it will pull up record is 1 > > that will containt > > > > <html> > > <head> > > <meta NAME="ROBOTS" CONTENT="All"> > > > > </head> > > <body bgcolor="#ffffff" topmargin="0" leftmargin="0" > > marginheight="0" > > marginwidth="0"> > > WHATEVER HTML CONTENT GOES INTO HERE > > Now with the next php script I want to pull in php script that > > pulls up my banner ad > > > > > > > > eval(<?php > > if > > (@include('/large/home/www/carmelme/admanager/phpadsnew.inc.php')) { > > if (!isset($phpAds_context)) $phpAds_context = array(); > > $phpAds_raw = view_raw ('', 4, '', '', > > '0', $phpAds_context); > > echo $phpAds_raw['html']; > > } > > ?>) > > </body> > > > > </html> > > > > Is that how I do it??? > > > > > > > > > > Quoting "CPT John W. Holmes" <holmes072000@charter.net>: > > > > > use eval(), but there has to be a better method for whatever > > you're doing. > > > > > > FYI: You don't "get nothing" for the PHP code. It's in an HTML > > file, so the > > > browser interprets that as some kind of HTML tag that it > > doesn't recognize, > > > so nothing is rendered. You'll see your PHP code in the source > > if you look > > > at it, though. > > > > > > ---John Holmes... > > > > > > ----- Original Message ----- > > > From: "Apollo (Carmel Entertainment)" <lists@carmelme.com> > > > To: <php-general@lists.php.net> > > > Sent: Wednesday, April 09, 2003 4:09 PM > > > Subject: Re: [PHP] How do I insert PHP script into existing script? Php > > > script within script? > > > > > > > > > > Duh! Already did. Is that how you treat all novices here? > > > > > > > > Again here is my problem. > > > > Lets say I enter <?php echo $_SERVER["HTTP_USER_AGENT"]; ?> > > in that HTML > > > that is > > > > residing in that database record, once I pull up that page I > > get nothing > > > in the > > > > area of that "user agent" PHP script. Is there anything I can > > do so that > > > script > > > > within a script would work or not. If yes, could tell me how, > > if now, than > > > just > > > > say "no, you novice, you can't do that". > > > > > > > > Quoting Chris Hayes <chayes@antenna.nl>: > > > > > > > > > Read a manual and the first chapter will explain it to you in a much > > > better > > > > > and complete way than i could type here for you. > > > > > Find manuals on www.php.net, or just like anywhere, ask > > Google for a php > > > > > tutorial. > > > > > > > > > > > > > > > At 21:46 9-4-2003, you wrote: > > > > > >I use following script for pages to pull up their html. > > NOTE: yes I am > > > > > still > > > > > >stuck in HTML, since I have no time to delve into PHP. > > > > > >Basicly if you go to page whatever.html and id of that page in the > > > script is > > > > > 1 > > > > > >it pulls up HTML from the database record. I did it this > > way so I can > > > just > > > > > >edit > > > > > >HTML in the database and not need to upload or download > > files. But now > > > I > > > > > >want to > > > > > >add extra features to some pages like PHP forms. What do I have to > > > enter in > > > > > my > > > > > >HTML so I could insert PHP script in there and not need to redo > > > anything > > > > > with > > > > > >the following script here? > > > > > > > > > > > ><?php > > > > > > $db = mysql_connect("host", "username", > > > > > > "password"); > > > > > > if( !$db ) > > > > > > { > > > > > > die("Error connecting to the Server"); > > > > > > exit; > > > > > > } > > > > > > $result = mysql_select_db("www", $db); > > > > > > if( !$result ) > > > > > > { > > > > > > die("Error selecting Database"); > > > > > > exit; > > > > > > } > > > > > > > > > > > >?> > > > > > ><?php > > > > > > $query = "SELECT > > > > > > * > > > > > >FROM > > > > > > html > > > > > >WHERE > > > > > >html.id='1'"; > > > > > > $result = mysql_query($query,$db); > > > > > > if( !$result ) > > > > > > { > > > > > > die("No record"); > > > > > > } > > > > > > { > > > > > > $code = > > mysql_result($result,$row,"code"); > > > > > > echo "$code"; > > > > > > } > > > > > > mysql_free_result($result); > > > > > > mysql_close(); > > > > > >?> > > > > > > > >

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