Re: How do I insert PHP script into existing script? Php script within script?
| From: | Carmel Entertainment) | Date: | Wed, 09 Apr 2003 20:57:51 +0000 |
| Subject: | Re: How do I insert PHP script into existing script? Php script within script? | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-143204@lists.php.net to get a copy of this message | ||
So let me see if I get you right.
This is my html page on the server is named whatever.html
page contains:
<?php
$db = mysql_connect("host", "username", "password");
if( !$db )
{
die("Error connecting to the Server");
exit;
}
$result = mysql_select_db("www", $db);
if( !$result )
{
die("Error selecting Database");
exit;
}
?>
<?php
$query = "SELECT
*
FROM
html
WHERE
html.id='1'";
$result = mysql_query($query,$db);
if( !$result )
{
die("No record");
}
{
$code = mysql_result($result,$row,"code");
echo "$code";
}
mysql_free_result($result);
mysql_close();
?>
Then when you go into database it will pull up record is 1
that will containt
<html>
<head>
<meta NAME="ROBOTS" CONTENT="All">
</head>
<body bgcolor="#ffffff" topmargin="0" leftmargin="0"
marginheight="0"
marginwidth="0">
WHATEVER HTML CONTENT GOES INTO HERE
Now with the next php script I want to pull in php script that pulls up my banner ad
eval(<?php
if (@include('/large/home/www/carmelme/admanager/phpadsnew.inc.php')) {
if (!isset($phpAds_context)) $phpAds_context = array();
$phpAds_raw = view_raw ('', 4, '', '', '0',
$phpAds_context);
echo $phpAds_raw['html'];
}
?>)
</body>
</html>
Is that how I do it???
Quoting "CPT John W. Holmes" <holmes072000@charter.net>:
> use eval(), but there has to be a better method for whatever you're doing.
>
> FYI: You don't "get nothing" for the PHP code. It's in an HTML file, so the
> browser interprets that as some kind of HTML tag that it doesn't recognize,
> so nothing is rendered. You'll see your PHP code in the source if you look
> at it, though.
>
> ---John Holmes...
>
> ----- Original Message -----
> From: "Apollo (Carmel Entertainment)" <lists@carmelme.com>
> To: <php-general@lists.php.net>
> Sent: Wednesday, April 09, 2003 4:09 PM
> Subject: Re: [PHP] How do I insert PHP script into existing script? Php
> script within script?
>
>
> > Duh! Already did. Is that how you treat all novices here?
> >
> > Again here is my problem.
> > Lets say I enter <?php echo $_SERVER["HTTP_USER_AGENT"]; ?> in that HTML
> that is
> > residing in that database record, once I pull up that page I get nothing
> in the
> > area of that "user agent" PHP script. Is there anything I can do so that
> script
> > within a script would work or not. If yes, could tell me how, if now, than
> just
> > say "no, you novice, you can't do that".
> >
> > Quoting Chris Hayes <chayes@antenna.nl>:
> >
> > > Read a manual and the first chapter will explain it to you in a much
> better
> > > and complete way than i could type here for you.
> > > Find manuals on www.php.net, or just like anywhere, ask Google for a php
> > > tutorial.
> > >
> > >
> > > At 21:46 9-4-2003, you wrote:
> > > >I use following script for pages to pull up their html. NOTE: yes I am
> > > still
> > > >stuck in HTML, since I have no time to delve into PHP.
> > > >Basicly if you go to page whatever.html and id of that page in the
> script is
> > > 1
> > > >it pulls up HTML from the database record. I did it this way so I can
> just
> > > >edit
> > > >HTML in the database and not need to upload or download files. But now
> I
> > > >want to
> > > >add extra features to some pages like PHP forms. What do I have to
> enter in
> > > my
> > > >HTML so I could insert PHP script in there and not need to redo
> anything
> > > with
> > > >the following script here?
> > > >
> > > ><?php
> > > > $db = mysql_connect("host", "username",
> > > > "password");
> > > > if( !$db )
> > > > {
> > > > die("Error connecting to the Server");
> > > > exit;
> > > > }
> > > > $result = mysql_select_db("www", $db);
> > > > if( !$result )
> > > > {
> > > > die("Error selecting Database");
> > > > exit;
> > > > }
> > > >
> > > >?>
> > > ><?php
> > > > $query = "SELECT
> > > > *
> > > >FROM
> > > > html
> > > >WHERE
> > > >html.id='1'";
> > > > $result = mysql_query($query,$db);
> > > > if( !$result )
> > > > {
> > > > die("No record");
> > > > }
> > > > {
> > > > $code = mysql_result($result,$row,"code");
> > > > echo "$code";
> > > > }
> > > > mysql_free_result($result);
> > > > mysql_close();
> > > >?>
> > > >
> > > >
> > > >--
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