Re: Email DataBase Results

From: Date: Mon, 21 Apr 2003 20:15:39 +0000
Subject: Re: Email DataBase Results
References: 1  Groups: php.general 
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Collect all data rows in one variable first, Try this: $query = "select * from table"; $result = mysql_db_query("$dbName", $query); $msg = ''; while ($r = mysql_fetch_array($result)) { $variable1 = $r["variable1"]; $variable2 = $r["variable2"]; $variable3 = $r["variable3"]; $msg.="$variable1 - $variable2 - $variable3 \n"; } mail("joecool@example.com", "My Subject", $msg); ----- Original Message ----- From: "Robert Pruitt" <rpruitt@Mid-tn.com> To: <php-general@lists.php.net> Sent: Monday, April 21, 2003 10:59 PM Subject: [PHP] Email DataBase Results > $query = "select * from table"; > $result = mysql_db_query("$dbName", $query); > while ($r = mysql_fetch_array($result)) { > $variable1 = $r["variable1"]; > $variable2 = $r["variable2"]; > $variable3 = $r["variable3"]; > } > > mail("joecool@example.com", "My Subject", "$variable1 - $variable2 - > $variable3"); > > > What is the best way to include the results of this query into the > mail() function? > > The above trial will not give full results. > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >

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