Re: newbie: help with array

From: Date: Mon, 28 Apr 2003 13:14:30 +0000
Subject: Re: newbie: help with array
References: 1 2  Groups: php.general 
Request: Send a blank email to php-general+get-145522@lists.php.net to get a copy of this message
The check permission only works when the permission is in the array. When the array does not contain the required permission the following error is thrown: Notice: Undefined offset: 3 in C:\Inetpub\...\menu.php on line 29 Any ideas what may be casuing this? Thanks for your help so far. "Marek Kilimajer" <kilimajer@webglobe.sk> wrote in message news:3EAD0B3E.9050901@webglobe.sk... > Something like: > // set permissions > while($perm = mysql_fetch_assoc($res)){ > $_SESSION['userPermissions'][$perm['userPermission']]=1; > } > > //check permission > if($_SESSION['userPermissions']['read']) { > //is allowed to read > } > > patlebon wrote: > > >I have database table that contains userId and permissionId. I want to query > >this table and make an array/list of permissions for a user when they login > >and assign these to a session variable called $_SESSION["userPermissions"]. > >On other pages i want to check if their $_SESSION["userPermissions"] array > >contains certain permissions and only allow certian bits of code to be > >displayed if it does. > > > >I have the query to get the permissions from the database but after this im > >not sure what to do. > > > >Any help on how to do this would be much appreciated. > > > > > > > > > > >

« previous php.general (#145522) next »