Re: newbie: help with array

This is just a notice about undefined offset. You can get rid of it by using if(array_key_exists('read', $_SESSION['userPermissions'])) instead, just more typing. patlebon wrote:

The check permission only works when the permission is in the array. When the array does not contain the required permission the following error is thrown: Notice: Undefined offset: 3 in C:\Inetpub\...\menu.php on line 29 Any ideas what may be casuing this? Thanks for your help so far. "Marek Kilimajer" <kilimajer@webglobe.sk> wrote in message news:3EAD0B3E.9050901@webglobe.sk...

Something like: // set permissions while($perm = mysql_fetch_assoc($res)){ $_SESSION['userPermissions'][$perm['userPermission']]=1; } //check permission if($_SESSION['userPermissions']['read']) { //is allowed to read } patlebon wrote:

I have database table that contains userId and permissionId. I want to

query

this table and make an array/list of permissions for a user when they

login

and assign these to a session variable called

$_SESSION["userPermissions"].

On other pages i want to check if their $_SESSION["userPermissions"]

array

contains certain permissions and only allow certian bits of code to be displayed if it does. I have the query to get the permissions from the database but after this

im

not sure what to do. Any help on how to do this would be much appreciated.