Re: Simple @#%@#% array/function not working....
| From: | Pablo | Date: | Sun, 11 May 2003 14:42:14 +0000 |
| Subject: | Re: Simple @#%@#% array/function not working.... | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-147207@lists.php.net to get a copy of this message | ||
On 05/11/2003 9:13 AM, Ryan A (ryan@jumac.com) wrote:
> I have an array and its working fine, but when i try to call a function that
> checks if the array isset i dont get the required output.
> Heres the code below:
>
> if (is_array($id)) { print "<pre>\$id = "; print_r($id); print
> "</pre>\n"; } //working fine
> $result = count ($id); //working fine
> print($result); //working fine
>
> function one()
> {
> if(isset($id[0]))
> return("test=".$id[0]);
> }
> echo "<h1>testing".one()."</h1>"; //HERES the problem, this is
> only
> printing "testing" instaed of "testing(array value)"
As written, one() doesn't know about $id. Either pass $id to one():
function one($id)
{
if(isset($id[0]))
return("test=".$id[0]);
}
echo "<h1>testing".one($id)."</h1>";
Or use global:
function one()
{
global $id;
if(isset($id[0]))
return("test=".$id[0]);
}
Pablo