Re: Simple @#%@#% array/function not working....

In article <005f01c317c7$802c6630$1701400a@l2zcaxu7emppqh>, ryan@jumac.com says... > Hi, > Am kind of new to php and brand new to arrays so please excuse me if this is > a stupid way of doing things. > > I have an array and its working fine, but when i try to call a function that > checks if the array isset i dont get the required output. > Heres the code below: > > if (is_array($id)) { print "<pre>\$id = "; print_r($id); print > "</pre>\n"; } //working fine > $result = count ($id); //working fine > print($result); //working fine > > function one() > { > if(isset($id[0])) > return("test=".$id[0]); > } > echo "<h1>testing".one()."</h1>"; //HERES the problem, this is > only > printing "testing" instaed of "testing(array value)" > > > Any ideas? Yes. To access the value of $id[] in the function you either need to pass it as a parameter to the function, or declare it global in the function. Then you might want to assign the return from the function to a variable which you then echo. You might want to read up on the scope of variables in the manual. -- Quod subigo farinam $email =~ s/oz$/au/o;