Re: ereg_replace()

In article <Pine.LNX.4.21.0009062128300.15883-100000@northface.intercarve.net>, dvogel@intercarve.net ("Drew P. Vogel") wrote: not 100% sure this is your answer, but with ereg or eregi, if you use paranthesis to store values, you need to use the following syntax: $matchRegex = "\[(.) (.)+ \]"; while (eregi($matchRegex,$templateLine,$regs)) { $templateLine = eregi_replace($matchRegex, filter($regs[2],$regs[1]),$templateLine); } the third optional parameter of ereg is the name of a variable that will contain an array of the parathesisized patterns. The [0] index stores the entire string, so the first () would be accessed via the [1] offset of the array. hope this helps, Jeff > Hi. I am having a problem using a function as the second argument to > ereg_replace(). > > This is an excerpt from my code. Within the filer() function, the > paramaters act differently in different functions. > > BEGIN EXCERPT > > $matchRegex = "\[(.) (.)+ \]"; > while ( eregi( $matchRegex, $templateLine ) ) { > $templateLine = eregi_replace( $matchRegex, filter( "\\2", "\\1" ), > $templateLine ); > } > > function filter ( $phrase, $flags ) { > > END EXCERPT > > 'echo $flags;' outputs "\1", where 'return $flags;' returns > "L" (it is > supposed to return "L"). Is this a bug in php? Am I misunderstanding the > use of \\n? > > --Drew Vogel > >