RE: [PHP] How to access a program outside of PHP?

From: Date: Wed, 10 Sep 2003 16:40:15 +0000
Subject: RE: [PHP] How to access a program outside of PHP?
Groups: php.general 
Request: Send a blank email to php-general+get-162197@lists.php.net to get a copy of this message
> Backticks is simply the ` sign (usually the character above the tab). > Popularly know as hair on the ear in my country :-) > for example if you want to invoke ls from php you just type > > $result = ls; > > hey presto the output from ls is now in your $result variable. Ohhh okay. Well if you mean to do this, $szPipe = popen(`/htdocs/gs -q -dNOPAUSE -dBATCH -sDEVICE=pdfwrite -sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf /htdocs/Sep08-113523.pdf`, "r");. This does not seem change anything. If I do this with the system() example, I get "Warning: system(): Cannot execute a blank command in /htdocs/index.php on line 14".

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