Re: How to access a program outside of PHP?

btw have you checked if you are in safe_mode? in php.ini error level can also be set in php.ini my guess is that you have a problem in your chroot setup. best regards Adam Douglas wrote:

Mmm... okay. I tried that and nothing. Is there no way for me to determine what the problem is? Error message some place, log file, etc? I do not understand why this is not work. Even a simple example from the PHP manual on system() does not work.

I meant to do this: $szPipe = `/htdocs/gs -q -dNOPAUSE -dBATCH -sDEVICE=pdfwrite -sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf /htdocs/Sep08-113523.pdf`;

Backticks is simply the ` sign (usually the character above

the tab).

Popularly know as hair on the ear in my country :-) for example if you want to invoke ls from php you just type $result = ls; hey presto the output from ls is now in your $result variable.

Ohhh okay. Well if you mean to do this, $szPipe =

popen(`/htdocs/gs -q

-dNOPAUSE -dBATCH -sDEVICE=pdfwrite -sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf /htdocs/Sep08-113523.pdf`, "r");. This does not seem change

anything. If I

do this with the system() example, I get "Warning: system():

Cannot execute

a blank command in /htdocs/index.php on line 14".

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