RE: [PHP] Dynamically generating PHP functions?

I dont think you need to make a dynamic function, instead try putting your vars into an array then traverse that array like this $field = array(); $sql = "INSERT INTO table VALUES ("; foreach ($field as $key => $value) { $sql .= "'".addslashes($value)."'"; } $sql .=")"; $res = mysql_dbquery("database",$sql); hope this helpes. Bolke N.B. you are even able to put your field directly from the form into an array just call your vars something like $field[0],$field[1] etc -----Oorspronkelijk bericht----- Van: Joseph H Blythe [mailto:joe.blythe@binarylogic.com.au] Verzonden: Friday, September 15, 2000 6:31 AM Aan: PHP-General Onderwerp: [PHP] Dynamically generating PHP functions? Hey, I have written a script that dynamically generates a form from a given database and table that would be suitable, as a generic data input device for any mysql table. My problem is that when I have tried to write the script for the forms action i.e.: ... mysql("database","INSERT INTO table Values ( '$field1', '$field2', '$field3', '$field4' )"); I cannot figure out how to generate the above function dynamically so that that it has the correct number of fields for the given database table, does anyone know how one would go about writing php functions dynamically then executing them? I suppose it is much the same as the way php dynamically generates html, but I need it to do it on itself, if this makes any sense. Any help would be much appreciated. Joseph -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net