Re: Dynamically generating PHP functions?

can we have a look at the script / form that you are trying to accomplish this from? Not really sure of what you are trying to achieve, what about using $fields = mysql_num_fields($result); then pass $fields along to the form processing script. -- Kind Regards Aaron Sinclair Webmaster, Regional Communications Mercy Ships-Pacific http://www.mercyships-pacific.org.nz > From: Joseph H Blythe <joe.blythe@binarylogic.com.au> > Organization: Binary Logic > Date: Fri, 15 Sep 2000 15:01:04 +1030 > To: PHP-General <php-general@lists.php.net> > Subject: [PHP] Dynamically generating PHP functions? > > Hey, > > I have written a script that dynamically generates a form from a given > database and table that would be suitable, as a generic data input > device for any mysql table. > > My problem is that when I have tried to write the script for the forms > action i.e.: > > ... > mysql("database","INSERT INTO table Values ( > '$field1', > '$field2', > '$field3', > '$field4' > )"); > > > I cannot figure out how to generate the above function dynamically so > that that it has the correct number of fields for the given database > table, does anyone know how one would go about writing php functions > dynamically then executing them? > > I suppose it is much the same as the way php dynamically generates html, > but I need it to do it on itself, if this makes any sense. > > Any help would be much appreciated. > > Joseph > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net