Re: Problem in the output of an array
| From: | Robert Cummings | Date: | Sun, 30 Nov 2003 00:53:44 +0000 |
| Subject: | Re: Problem in the output of an array | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-171380@lists.php.net to get a copy of this message | ||
On Sat, 2003-11-29 at 19:47, Robert Cummings wrote:
> On Sat, 2003-11-29 at 19:29, sophie@sitadelle.com wrote:
> > I'm soory but your code doesn't make me understand what you want to do...
> > Be more precise, it will help you to get some help
> >
> > > I have this code, I would like, if this could be done
> > >
> > > <?
> > > $array['dim1']['dim2']['dim3'][3] = "value";
> > >
> > > $dim1 = 'dim1';
> > > $dim2 = 'dim2';
> > > $dim3 = 'dim3';
> > > $dim4 = 3;
> > >
> > > $test = "[$dim1][$dim2][$dim3][$dim4]";
> > > $result = "$array$test";
> > >
> > > echo $result;
> > > ?>
> > >
> > > The output is : Array[dim1][dim2][dim3][3]
> > >
> > > I need that the output was: value
>
Ignore my last answer, I read your problem wrong. Answer below:
<?
$array['dim1']['dim2']['dim3'][3] = "value";
$dim1 = 'dim1';
$dim2 = 'dim2';
$dim3 = 'dim3';
$dim4 = 3;
$test = '[$dim1][$dim2][$dim3][$dim4]';
$result = eval( 'return $array'.$test.';' );
echo $result;
?>
HTH,
Rob.
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