Re: Problem in the output of an array

From: Date: Sun, 30 Nov 2003 02:25:44 +0000
Subject: Re: Problem in the output of an array
References: 1 2 3 4  Groups: php.general 
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$result = eval( 'return $array'.$test.';' );
Um... echo $array[$dim1][$dim2][$dim3][$dim4]; eval == evil. I can't think of a single legimiate reason why you'd want/need to make a string "[$dim1]...." first, and if you have to I'd suspect that something is very wrong with the way you are writing your script. Feel free to prove me wrong, though :) John Robert Cummings writes:
On Sat, 2003-11-29 at 19:47, Robert Cummings wrote:
On Sat, 2003-11-29 at 19:29, sophie@sitadelle.com wrote:
I'm soory but your code doesn't make me understand what you want to do... Be more precise, it will help you to get some help
I have this code, I would like, if this could be done <? $array['dim1']['dim2']['dim3'][3] = "value"; $dim1 = 'dim1'; $dim2 = 'dim2'; $dim3 = 'dim3'; $dim4 = 3; $test = "[$dim1][$dim2][$dim3][$dim4]"; $result = "$array$test"; echo $result; ?> The output is : Array[dim1][dim2][dim3][3] I need that the output was: value
Ignore my last answer, I read your problem wrong. Answer below: <? $array['dim1']['dim2']['dim3'][3] = "value"; $dim1 = 'dim1'; $dim2 = 'dim2'; $dim3 = 'dim3'; $dim4 = 3; $test = '[$dim1][$dim2][$dim3][$dim4]'; $result = eval( 'return $array'.$test.';' ); echo $result; ?> HTH, Rob. -- .------------------------------------------------------------. | InterJinn Application Framework - http://www.interjinn.com | :------------------------------------------------------------: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn |
| also provides an extremely flexible architecture for       |
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