Re: Having trouble formatting width using printf() and default spaces
| From: | Jason Barnett | Date: | Tue, 30 Mar 2004 23:43:53 +0000 |
| Subject: | Re: Having trouble formatting width using printf() and default spaces | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-181880@lists.php.net to get a copy of this message | ||
David Scott wrote:
I'm using a for() loop to generate random die rolls. I'd like the numbers to be formatted in a grid.In a grid... like an HTML table? You could something like: $row = 20; $col = 5; echo '<table>'; for ($i = 1; $i < $row; $i++) {
echo '<tr>';
for ($j = 1; $j < $col; $j++) {
echo '<td>'.rand(1, $sides).'</td>';
}
echo '</tr>';
}
echo '</table>';
for ($i = 0; $i < 100; $i++) {
if (!($i % 5)) {
print("<br />");
}
printf("%'.10u", rand(1,$sides));
}
Currently, I'm padding with '.', but I'd like to pad with the default spaces.
For example, printf("%10u", rand(1,$sides)); Except the numbers end up like,
7 10 14 19 3
4 6 16 13 2
etc.
Why is it that when I leave out the padding character, the output isn't padded?