Re: Having trouble formatting width using printf() and default spaces

I tried your method and it's a nice variation, though it leaves me with two issues: 1. I'd like the numbers to be right-aligned. 2. I'd still like to understand why the default padding of spaces isn't working for printf(). If I could get printf() to pad with spaces, it would be exactly what I'm after. Jason Barnett wrote:

David Scott wrote:

I'm using a for() loop to generate random die rolls. I'd like the numbers to be formatted in a grid.

In a grid... like an HTML table? You could something like: $row = 20; $col = 5; echo '<table>'; for ($i = 1; $i < $row; $i++) {

    echo '<tr>';
    for ($j = 1; $j < $col; $j++) {
        echo '<td>'.rand(1, $sides).'</td>';
    }
    echo '</tr>';

} echo '</table>';

for ($i = 0; $i < 100; $i++) {

    if (!($i % 5)) {
        print("<br />");
    }
    printf("%'.10u", rand(1,$sides));

} Currently, I'm padding with '.', but I'd like to pad with the default spaces. For example, printf("%10u", rand(1,$sides)); Except the numbers end up like, 7 10 14 19 3 4 6 16 13 2 etc. Why is it that when I leave out the padding character, the output isn't padded?