Re: regex question...

Hi, My suggestion is to use preg for benefit of the non-greedy operator: $new = preg_replace("@(<!--BeginCode-->).*?(<!--EndCode-->)@si", "\\1$whatever\\2", $str); Ciao, Andreas Pour http://www.kde.com/ : Everything KDE http://apps.kde.com/: The Latest in KDE Applications Remco Chang wrote: > > hi, > > i have a quick regex question. > > i have a rather large string which looks like: > $str = " > : > : > <!--BeginCode--> > hello world! > <!--EndCode--> > : > : > "; > > i would like to write a function that would replace the hello world > part... so far, i have come up with: > > $pattern = "<!--BeginCode-->[^\\]*<!--EndCode-->"; > $newStr = ereg_replace ($pattern, "how you doing?" $str); > > the problem with this is that i cannot have the \ sign in my string... so > i was wondering if i could have something that's equivalent to > [[:any_character_digits_symbols:]]... i tried [^\0] but that didn't work. > :P > > thanx in advance for any help! :) > > ---------------- > remco chang > bountyquest.com