Re: forms/variables/create database

try this : $link = mysql_connect($host, $user, $pass); Note : No SINGLE quotes. In PHP, quotations are as follows $host = 'localhost'; $a = '$host'; $b = "$host"; echo $a; that prints $host echo $b; that prints localhost. HTH -Minuk ----- Original Message ----- From: "bigmark" <neretlis@westnet.com.au> To: <php-general@lists.php.net> Sent: Sunday, October 10, 2004 10:23 PM Subject: [PHP] forms/variables/create database

hi, does anyone know why this is not working, i have married 2 pieces of code together and i have no idea what im doing--any help is appreciated. I get an error that says it cant find the host--$host so obviusly its not passing it from the form. ///////////////////////////////////////// <?php $host = $_POST['host']; $user = $_POST['user']; $pass = $_POST['pass']; $db_name = $_POST['db-name']; $link = mysql_connect('$host', '$user', '$pass'); if (!$link) { die('Could not connect: ' . mysql_error()); } if (mysql_create_db('db_name')) { echo "Database created successfully\n"; } else { echo 'Error creating database: ' . mysql_error() . "\n"; } ?> ///////////////////////////////////////////// -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php