Re: forms

Thanks-- i got that going-GREAT ! now i have a form that creates the database and tables, any ideas how i can get this info to change the connect_db file so that it doesnt have to be done manually. "Minuk Choi" <Choi.Minuk@verizon.net> wrote in message news:000401c4af3f$858bf940$0200a8c0@koryo... > try this : > > $link = mysql_connect($host, $user, $pass); > > Note : No SINGLE quotes. > > In PHP, quotations are as follows > > $host = 'localhost'; > $a = '$host'; > $b = "$host"; > > echo $a; > > that prints $host > > echo $b; > > that prints localhost. > > HTH > -Minuk > > > ----- Original Message ----- > From: "bigmark" <neretlis@westnet.com.au> > To: <php-general@lists.php.net> > Sent: Sunday, October 10, 2004 10:23 PM > Subject: [PHP] forms/variables/create database > > > > hi, does anyone know why this is not working, i have married 2 pieces of > > code together and i have no idea what im doing--any help is appreciated. > > I get an error that says it cant find the host--$host so obviusly its not > > passing it from the form. > > > > ///////////////////////////////////////// > > <?php > > $host = $_POST['host']; > > $user = $_POST['user']; > > $pass = $_POST['pass']; > > $db_name = $_POST['db-name']; > > > > > > $link = mysql_connect('$host', '$user', '$pass'); > > if (!$link) { > > die('Could not connect: ' . mysql_error()); > > } > > > > if (mysql_create_db('db_name')) { > > echo "Database created successfully\n"; > > } else { > > echo 'Error creating database: ' . mysql_error() . "\n"; > > } > > ?> > > ///////////////////////////////////////////// > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > >