Re: php variables in a backtick command

So I tried it that way and it worked, that is annoying though, having to add extra lines to the code and assign the contents of one variable to another. Any way around this? Jonathan "Jonathan Duncan" <jonathan@nacnud.com> wrote in message news:20041212010917.20923.qmail@pb1.pair.com... >I am trying to run a shell command with backticks. However, I get a parse >error. Is it because I have an array variable in there? > > $result = > `adduser -l=$dist_id -p=$user['password'] --f="$user['name_first'] > $user['name_last']"`; > > Do I need to assign the value to a regular variable before I put it in > there? Like this? > > $pword=$user['password'] > $fname =$user['name_first'] > $lname =$user['name_last'] > $result = adduser -l=$dist_id -p=$pword --f="$fname > $lname"; > > Thanks, > Jonathan